An engine pulls a car of mass 1500kg on a level road at constant speed of 5m/s.If the frictional force is 500N,what power does the engine generate?

F=m x a

500N=1500kg x a

a=500N/1500kg  = a=0.3ms^-2

Third law of motion:

2as=v²-u²

2(o.3)s=25

s=25/0.6

s=41m  (appx)

Now  w= f x s

  = 500x 41

  = 20500joules  (appx)

second law of motion:

  s=ut+1/2at²

  41=1/2 (o.3)(t²)

  0.3(t²)=82

  t²=82/0.3

  t²= 273

  t=16.5s  (appx)

now  power=work done/ time taken

  p=20500/16.5

  power=1242Js^-1  (appx)