An exterior angle of a triangle is 80 degrees, one of its opposite interior angles is 60 degrees. Then the measure of other interior opposite angle is

 

Let ABC be the  in which side BC is produced to D such that ACD is the exterior angle.Let ACD = 80°Now, ABC and BAC are the interior  opposite angles.Let ABC = 60°Now, BAC = ?We know that, ,easure of exterior angle is equal to sum of interior opposite angles.Now, ACD = ABC + BAC80° = 60° + BACBAC = 20°

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pls tell me fast
 
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20 degrees.
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