An ore contains 12% copper.how many kilograms of the ore are required to get 69 kg of copper?

Suppose total amount of ore required is xPercentage of copper=12% i.e. 12kg of copper in 100kg of oreAmount of copper=69kgSince 100 kg of ore contains 12 kg of copperso 1kg of ore contains 12100kg of copper.therefore x kg of ore contains 12x100kg of copperFor x kg of ore to contain 69 kg of copper we must have;12x100=69x=69×10012=575Therefore 575kg of ore contains 69 kg of copper.

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