An organic compund was found to contain 40% carbon, 6.66% hydrogen. finds its emperical formula

Element |
Atomic mass |
Percentage |
Atomic ratio |
Simplest ratio |

Carbon | 12 | 40.0 | $\frac{40}{12}=3.33$ | $\frac{3.33}{3.33}=1$ |

Hydrogen | 1 | 6.66 | $\frac{6.66}{1}=6.66$ | $\frac{6.66}{3.33}=2$ |

Oxygen | 16 | 53.34 | $\frac{53.34}{16}=3.33$ | $\frac{3.33}{3.33}=1$ |

Empirical formula is CH

_{2}O

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