An SHM is given as y=8 (sin 2 pi t + root 3 cos 2 pi t ) - Physics - Waves and Oscillations

Question

An SHM is given as y=8 (sin 2 pi t + root 3 cos 2 pi t ) find the
amplitude of the given wave Please try and answer

Vaibhav T. · Accepted Answer

Dear Student,

y=8sin2πt+3 cos2πty=8 sin2πt+83 cos2πtLet 8=R cosϕ83=R sinϕy=R cosϕ sin2πt+R sinϕ cos2πty=R sin2πt+ϕwhere, R is the amplitude of waveand ϕ is the initial phase
R=82+832R=64+192R=256=16

An SHM is given as y=8 (sin 2 pi t + root 3 cos 2 pi t ) . find the amplitude of the given wave . Please try and answer .