angular momentum in 2nd bohr orbit of H atom is x. then find out the angular momentum in 1st excited state of Li 2+ is what ?

Dear Student,

Angular momentum of 2nd Bohr orbit is x.
So, L = nh/2$\pi$ = 2h/2$\pi$ = h/$\pi$
For, Li2+, it is 2st excited state. This also means that n = 2.
As angular momentum does not depend on atomic number,
So, L = nh/2$\pi$ = 2h/2$\pi$ = h/$\pi$
Thus angular momentum of both the systems are same, i.e. x
The answer is x.

Regards