Dear student Class interval f xi di=xi-A where A=25 ui=di/h where h=5 fiui 7 5-12 5 6 10 -15 -3 -18 12 5-17 5 10 15 -10 -2 -10 17 5-22 5 p 20 -5 -1 -p 22 5-27 5 10 25 0 0 0 27 5-32 5 2 30 5 1 2 32 5-37 5 8 35 10 2 16 N=∑fi=36+p ∑fiui=-10-p Mean=A+h∑fiui∑fi⇒21=25+5-10-p36+p⇒-45=-10-p36+p⇒-144-4p=-50-5p⇒5p-4p=-50+144⇒p=94 Regards

ans.my ques plzz

Dear student

Class interval	f	x_i	d_i=x_i-A where A=25	u_i=d_i/h where h=5	f_iu_i
7.5-12.5	6	10	-15	-3	-18
12.5-17.5	10	15	-10	-2	-10
17.5-22.5	p	20	-5	-1	-p
22.5-27.5	10	25	0	0	0
27.5-32.5	2	30	5	1	2
32.5-37.5	8	35	10	2	16
	$N = \sum_{}^{} f_{i} = 36$ +p				$\sum_{}^{} f_{i} u_{i} = - 10 - p$

Mean = A + h \{\frac{\sum_{}^{} f_{i} u_{i}}{\sum_{}^{} f_{i}}\} \Rightarrow 21 = 25 + 5 \{\frac{- 10 - p}{36 + p}\} \Rightarrow - \frac{4}{5} = \frac{- 10 - p}{36 + p} \Rightarrow - 144 - 4 p = - 50 - 5 p \Rightarrow 5 p - 4 p = - 50 + 144 \Rightarrow p = 94

Regards

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