Ans Ans Kumar box *hare is — of Jessica Romu pt. share is — of the total mm•ber of sweets in bog Jessica receives 48 more sweets than K—. • (a) Of total numbe is All's sh•re? O') Hov ony sweets there io Share with your friends Share 0 Ankita Agarwal answered this Dear Student, Let x is sweets of Jessica y is sweets of kumar's z is Sweets of Ali's & T is total sweetsNow,Given conditions: Ali's sweets is 14 of Kumar and Jessica so, z=14(x+y)........iGiven condition: Jassica sweets is 35 of total so, x=35×T........iiGiven condition : Kumar sweets is more than of Jassicaso, y=x-48.......iiiAsTotal SweetT=x+y+z .....ivNow putting value of x from eqn ii in eqniiiy=35T-48.......vNow putting value of eqn ii in eqnv in eqniwe get z=1435T+35T-48......viNow putting value x,y,z from eqn ii,v &vi in eqnivwe getT=35T+35T-48+1435T+35T-48T=35T+35T-48+320T+320T-484T=12+12+3+320T-48-12T=3T2-603T2-T=60T=120now calculate value for zz=1435×120+35×120-48z=143×24+3×24-48z=1472+24z=964=24aSo ali Share will be=24120 Ali Share =15 answerb Total sweets in the box=120 answer Hope this information will clear your doubts about topic. If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible. Regards 0 View Full Answer Samra Imran answered this yes i too wanted 0 Hardik Gupta answered this Let x is sweets of Jessica. y is sweets of kumars z is Sweets of Ali' and t is total sweets 1. given condition Ali's sweets is 1/4 of Kumar and Ali's so z=1/4(x+y) 2. given condition jassica sweets is 3/5 of total so x=3/5*t 3. given kumar sweets is more than of jassica y=x-48 4. t=x+y+z solve all equations answ is t=120, x=72, y=24 and z=24 alis share is 24 and total sweet is 120 0