Ans

Ans Kumar box *hare is — of Jessica Romu pt. share is — of the total mm•ber of sweets in bog Jessica receives 48 more sweets than K—. • (a) Of total numbe is All's sh•re? O') Hov ony sweets there io

Dear Student,
 Let x is sweets of Jessica    y is sweets of kumar's   z is Sweets of Ali's & T is total sweetsNow,Given  conditions:  Ali's sweets is 14 of Kumar and Jessica so, z=14(x+y)........iGiven condition: Jassica sweets is 35 of total so,  x=35×T........iiGiven condition : Kumar sweets is more than of Jassicaso,  y=x-48.......iiiAsTotal SweetT=x+y+z .....ivNow putting value of x from eqn ii in eqniiiy=35T-48.......vNow putting value of eqn ii in eqnv in eqniwe get z=1435T+35T-48......viNow putting value x,y,z from eqn ii,v &vi in eqnivwe getT=35T+35T-48+1435T+35T-48T=35T+35T-48+320T+320T-484T=12+12+3+320T-48-12T=3T2-603T2-T=60T=120now calculate value for zz=1435×120+35×120-48z=143×24+3×24-48z=1472+24z=964=24aSo ali Share will be=24120              Ali Share =15 answerb Total sweets in the box=120  answer 

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yes i too wanted

 
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Let x is sweets of Jessica.
y is sweets of kumars
z is Sweets of Ali'
and t is total sweets

1. given condition  Ali's sweets is 1/4 of Kumar and Ali's
so
z=1/4(x+y)
2.  given condition jassica sweets is 3/5 of total
so x=3/5*t
3.  given kumar sweets is more than of jassica
y=x-48
4. t=x+y+z

solve all equations
answ is t=120, x=72, y=24 and z=24

alis share is 24 and total sweet is 120
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