Answer ASAP Pls.

Dear Student,

$$\begin{gathered} {\left(-4\right)}^2\times {\left(-4\right)}^{-3} \\ \mathrm{Using} \mathrm{property} \mathrm{of} \mathrm{exponents}:\hspace{0.17em}{\mathrm{x}}^{\mathrm{a}} \times {\mathrm{x}}^{\mathrm{b}}= {\mathrm{x}}^{\mathrm{a}+\mathrm{b}} \\ = {\left(-4\right)}^{2-3} \\ = {\left(-4\right)}^{-1} \\ \mathrm{Using} \mathrm{property} \mathrm{of} \mathrm{exponents}:\hspace{0.17em}{\mathrm{x}}^{-\mathrm{a}} = \frac{1}{{\mathrm{x}}^{\mathrm{a}}} \\ {(-4)}^{\mathbf{2}}\mathbf{\times }{(-4)}^{\mathbf{-}\mathbf{3}}\mathbf{=}\mathbf{ }\frac{\mathbf{1}}{\mathbf{-}\mathbf{4}} \end{gathered}$$
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