ANSWER ASAP!!
when 4 hydrogen nuclei combine to form a helium nucleus estimate the amount of energy in MeV released in this process of fusion .
given mass of H = 1.007825 u
mass of helium nucleus = 4.002603u
Mass defect ,
Δm = 4x(1.007825) - 4.002603 = 0.028697 u
E = 0.028697 x 931.5 MeV
= 26.73 MeV