Dear Student, Here is the solution : The roots of the equation can be found by the formula:-b±b2-4ac2aHere a=1, b = 99, c=127So the roots are : -99±992-4×1×1272×1= -99±9801-5082=-99±92932= -99±96 42= -1 2, -97 7So both roots are negative Regards,

Answer me 7 q

Dear Student,

Here is the solution :

T h e r o o t s o f t h e e q u a t i o n c a n b e f o u n d b y t h e f o r m u l a : \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a} H e r e a = 1, b = 99, c = 127 S o t h e r o o t s a r e : \frac{- 99 \pm \sqrt{99^{2} - 4 \times 1 \times 127}}{2 \times 1} = \frac{- 99 \pm \sqrt{9801 - 508}}{2} = \frac{- 99 \pm \sqrt{9293}}{2} = \frac{- 99 \pm 96.4}{2} = - 1.2, - 97.7 S o b o t h r o o t s a r e n e g a t i v e

Regards,

-1

View Full Answer