Answer of this question with definations.

Dear Student,time = 2 secNumber of electrons= 6×1023We know that,Q= itAlso, q=neso, i=net=6×1023×1.6×10-192=4.8×104 AAlso, V=W/q=46×1023×1.6×10-19=0.41×10-4 VoltSo, (i)=4.8×104 A(ii)= 0.41×10-4 VoltRegards

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