# answer plz fast

According to Newton's law of law of gravitational force of gravitational is inversely proportional to the square of distance between the bodies so distance is doubled force of gravitational will reduce by 1/4.

$F=G\frac{{m}_{1}{m}_{2}}{{R}^{2}}\phantom{\rule{0ex}{0ex}}WhereRisthediatncebetweenthebodies.So,ifR\prime =2R,then\phantom{\rule{0ex}{0ex}}F\text{'}=G\frac{{m}_{1}{m}_{2}}{{\left(2R\right)}^{2}}=\frac{1}{4}G\frac{{m}_{1}{m}_{2}}{{R}^{2}}=\frac{1}{4}F\phantom{\rule{0ex}{0ex}}$

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