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Answer question 2 please.

Thank you

Dear Student,

a) Here, the electric field for *r < a* is,

$E=0$

Because, this point is inside the conductor.

b) For region *a < r < b*,

By using Gauss law,

$\int E.dA=\frac{{Q}_{enclosed}}{{\epsilon}_{0}}\Rightarrow E\left(4\pi {r}^{2}\right)=\frac{q}{{\epsilon}_{0}}\phantom{\rule{0ex}{0ex}}\Rightarrow E=\frac{q}{4\pi {\epsilon}_{0}{r}^{2}}$

c) For a point, which is outside of the spheres, *i.e, r > c*,

$\int E.dA=\frac{{Q}_{enclosed}}{{\epsilon}_{0}}\Rightarrow E\left(4\pi {r}^{2}\right)=\frac{0}{{\epsilon}_{0}}\phantom{\rule{0ex}{0ex}}\Rightarrow E=0$

Hope this information will clear your doubts about the topic.

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