Answer question 2 please.
Thank you

Dear Student,


a) Here, the electric field for r < a is,


Because, this point is inside the conductor.

b) For region a < r < b,

By using Gauss law,

E.dA = Qenclosedε0E4πr2=qε0E=q4πε0r2

c) For a point, which is outside of the spheres, i.e, r > c,

E.dA = Qenclosedε0E4πr2=0ε0E=0


Hope this information will clear your doubts about the topic.

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