Answer question 2 please.
Thank you

Dear Student,

a) Here, the electric field for r < a is,

$E=0$

Because, this point is inside the conductor.

b) For region a < r < b,

By using Gauss law,

$$\begin{gathered} \int E.dA = \frac{Q_{enclosed}}{{\epsilon }_0}\Rightarrow E\left(4\pi r^2\right)=\frac{q}{{\epsilon }_0} \\ \Rightarrow E=\frac{q}{4\pi {\epsilon }_0{r}^2} \end{gathered}$$



c) For a point, which is outside of the spheres, i.e, r > c,

$$\begin{gathered} \int E.dA = \frac{Q_{enclosed}}{{\epsilon }_0}\Rightarrow E\left(4\pi r^2\right)=\frac{0}{{\epsilon }_0} \\ \Rightarrow E=0 \end{gathered}$$

Hope this information will clear your doubts about the topic.

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