Answer the 6th question "NO LINKS": 6 Given log10 x=a, log10 y=b and log10 z=c, (i) Write - Maths - Indices and Logarithms

Question

Answer the 6th question "NO LINKS":

6 Given log10 x=a, log10 y=b and
log10 z=c,
(i) Write down 102a-3 in terms of x
(ii) write down 103b-1 in terms of y
(iii) if log 10   P = 2 a + b 2 - 3 c , express P in
terms

Muskaan Talwar · Accepted Answer

Dear Student,

log10x=a, log10y=b, log10z=c⇒x=10a, y=10b, z=10ci Now, 102a-3=10a210-3=x21000ii Now, 103b-1=10b310-1=y310

The statement of (iii) is not complete

Regards

Answer the 6th question. "NO LINKS": 6. Given log10 x=a, log10 y=b and log10 z=c, (i) Write down 102a-3 in terms of x. (ii) write down 103b-1 in terms of y. (iii) if log 10 P = 2 a + b 2 - 3 c , express P in terms.

Answer the 6th question. "NO LINKS":

6. Given log₁₀ x=a, log₁₀ y=b and log₁₀ z=c,
(i) Write down 10^2a-3 in terms of x.
(ii) write down 10^3b-1 in terms of y.
(iii) if $\log_{10} P = 2 a + \frac{b}{2} - 3 c$ , express P in terms.