Answer the question number 3
3. The volume charge density within a volume V is  ρ ( r ) . What is the force on a small test charge  q 0  placed outside the volume  having position vector  r 0  with respect to the same origin considered to specify the position vector of the charge distribution within the volume.

Dear studentPlease find your answer in followingGiven that volume charge densiy V is ρ(r) and test charge q0 and position vector r0Now force on test charge is F=kq0qr2 here k is 14πεoF=kq0ρ(r)dτ r^ r20F=kq0ρ(r)r2sinθdrdθdφ r^ r20now integrate  ρ(r)sinθdrdθdφ =0r0π02π ρ(r)sinθdrdθdφ=q4πF=q0q4π r^4πεo=q0q r^εoI hope it will help you!Regards

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