Solution As we know I= Q t where Q=ne(number of electron× charge on each electron which is 1 6×10-19 ) Therefore, I= net = 62 5×1018×1 6×10-191 =10A

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Solution

A s w e k n o w I = \frac{Q}{t} ​ w h e r e Q = n e (n u m b e r o f e l e c t r o n \times c h a r g e o n e a c h e l e c t r o n w h i c h i s 1.6 \times 10^{- 19}) T h e r e f o r e, I = \frac{n e}{t} ​ = \frac{62.5 \times 10^{18} \times 1.6 \times 10^{- 19}}{1} ​ = 10 A