Answers this second question Share with your friends Share 0 Deepak Kumar answered this 0 View Full Answer Ammaar answered this let 'a' be any positive integer and b=2 By euclid's division algorithm a=bq+r 0≤r<b a=2q+r 0≤r<2 (i.e) r =0,1 r=0 , a=2q+0=> a=2q r=1, a=2q+1 if a is the form of 2m then 'a' is an even integer and positive odd integer is of the form 2m+1 1 Santanu Sahoo answered this Hi, Here is the solution : Regards! 0
