At 500k temperature in 2 liter vessel 0.325gm O2 gas is collected over water. If the vapour pressure of water is 32 bar at 500k, find the partial pressure of dry O2 gas?
The pressure of dry O2 can be calculated from subtracting the partial vapor pressure of H2O from total vapour pressure at that temperature.
Ptotal = PO2 + PH2O
Ptotal can be calculated using formula PV= nRT
P = nRT/V
n = 0.325g / 32 = 0.01moles
R = 0.083 bar K-1 mol-1
T = 500 K
V= 2 L
Putting value in formula we get
P = 0.01 * 0.083 * 500 /2 = 0.2075 bar
Pressure of H2O is 32 bar at 500K which is more than total pressure it means something is wrong in question.
Ptotal = PO2 + PH2O
Ptotal can be calculated using formula PV= nRT
P = nRT/V
n = 0.325g / 32 = 0.01moles
R = 0.083 bar K-1 mol-1
T = 500 K
V= 2 L
Putting value in formula we get
P = 0.01 * 0.083 * 500 /2 = 0.2075 bar
Pressure of H2O is 32 bar at 500K which is more than total pressure it means something is wrong in question.