At a certain temperature 2HI gives H2and I2(reversible reaction) Only 50% HI is dissociated at equilibrium The equilibrium - Chemistry - Equilibrium

Question

At a certain temperature 2HI gives H2and I2(reversible reaction)
Only 50% HI is dissociated at equilibrium The equilibrium constant
is

Geetha · Accepted Answer

2 HI →    H2  +  I2Initial   moles    2             1          1At eqm             2-2X      X         X        (where X is the amount dissociated)X = 0
5 (since 50% dissociation)                           2-2(0
5)  0 5     0
5                             1              0
5     0
5KC = [H2] [I2][HI]2 = 0
5 × 0 512 = 0 25

At a certain temperature 2HI gives H2and I2(reversible reaction) .Only 50% HI is dissociated at equilibrium .The equilibrium constant is .