At temperature T, a compound AB2 (g) diassociates according to the reaction :
2AB2(g) [reverisble sign ] 2AB(g) + B2.
with degree of dissociation, x, which is small compared to unity. Deduce the expression for x in terms of equillibrium constant Kp and the total pressure.
Hi,
The answer to your question is as follows:
2AB2 (g) ↔ 2AB (g) + B2(g)
Initially pi 0 0
At equ pi-2x 2x x
Therefore P (Total pressure) = pi + x or x= p-pi
Now Kp = p(B2) p (AB)2/(pAB2)2