Calculate bond order of oxygen molecule. List all the information provided by the bond about this molecule.( electronic configuration, magnetic property ) Share with your friends Share 0 Vartika Jain answered this Dear Student, MO configuration of O2 = (σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(σ2pz)2(π2px)2(π2py)2(π*2px)1(π*2py)1Number of bonding electrons, Nb= 10Number of antibonding electrons, Na=6Therefore, bond order=Nb-Na2=10-62=42=2Since the last orbital contains unpaired electron, therefore, it will be paramagnetic. 0 View Full Answer
