Calculate delta H f for chloride ion from data- 1/2H2 (g) + 1/2Cl2 (g) = HCl (g) del H f - Chemistry - Thermodynamics

Question

Calculate delta H°f for chloride ion from data- 1/2H2 (g) +
1/2Cl2 (g) = HCl (g) del H°f = -92 4 kJ HCl (g) + nH2O = H+
(aq) + Cl- (aq) del H°f = -74 8 kJ Delta H°f H+ (aq) =0 0
kJ Answer is -167 2 kJ Pls solve

Vartika Jain · Accepted Answer

Dear User,
12H2 (g) + 12Cl2 (g) → HCl (g)                           ∆H°f = -92
4 kJ        
(i)HCl (g) + nH2O → H+ (aq) + Cl-(aq)                 ∆H°f = -74
8 kJ        
(ii)We have to calculate ∆H°f for the reaction :12Cl2 → Cl-Add eq
 (i) and (ii) we get,12H2 (g) + 12Cl2 (g) + nH2O → H+ (aq) + Cl-(aq)  Now, the enthalpy of formation of H+ is 0 i
e
 in the above reaction the enthalpy is there for the formation of chloride only,i
e    ∆H°f = -92
4 kJ + (-74
8 kJ)                    = =167
2 kJ

Calculate delta H°f for chloride ion from data- 1/2H2 (g) + 1/2Cl2 (g) = HCl (g) del H°f = -92.4 kJ HCl (g) + nH2O = H+ (aq) + Cl- (aq) del H°f = -74.8 kJ Delta H°f H+ (aq) =0.0 kJ Answer is -167.2 kJ Pls solve