Calculate percentage of each element in Al2(So4)3 (Al=27, s=32, O=16).

Dear Student,
  • Relative atomic masses: Al = 27, S = 32 and O = 16
  • Relative formula mass = 2x27 + 3x(32 + 4x16) = 342
  • There are 4 x 3 = 12 oxygen atoms, each of relative atomic mass 16,
  • Total mass of oxygen in the formula of 12 x 16 = 192
  •  Percentage of oxygen in Al2(SO4)3 = 100 x 192 / 342 = 56.1% oxygen by mass in aluminium sulphate
  •  Percentage of Sulphur in Al2(SO4)3 = 100 x 96 / 342 = 28.07% oxygen by mass in aluminium sulphate
  •  Percentage of Aluminium in Al2(SO4)3 = 100 x54 / 342 =  15.78 % oxygen by mass in aluminium sulphate
Regards

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WE ARE GIVEN WITH ATOMIC UNIT MASS OF Al S and O

Formula : Al2(SO4)3

=2*Al + 3*1*S + 4*3*O
=2*27 + 3*32 + 12*16
=54+64+192
=310

PERCENTAGE OF AL=17.419
PERCENTAGE OF S= 20.645
PERCENTAGE OF O=61.935
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