Calculate percentage of each element in Al2(So4)3 (Al=27, s=32, O=16).
Dear Student,
- Relative atomic masses: Al = 27, S = 32 and O = 16
- Relative formula mass = 2x27 + 3x(32 + 4x16) = 342
- There are 4 x 3 = 12 oxygen atoms, each of relative atomic mass 16,
- Total mass of oxygen in the formula of 12 x 16 = 192
- Percentage of oxygen in Al2(SO4)3 = 100 x 192 / 342 = 56.1% oxygen by mass in aluminium sulphate
- Percentage of Sulphur in Al2(SO4)3 = 100 x 96 / 342 = 28.07% oxygen by mass in aluminium sulphate
- Percentage of Aluminium in Al2(SO4)3 = 100 x54 / 342 = 15.78 % oxygen by mass in aluminium sulphate