Calculate the concentration of nitric acid in moles per litre in a sample which has a density, 1.41 g mL–1 and the mass per cent of nitric acid in it being 69%

Hi,
 
Mass percent of HNO3=69%
Hence mass of HNO3 in the solution is 69g
Mass of water=100-69=31g
Number of moles of HNO3 =69/63=1.09moles
Density=mass/volume
Volume=mass/density
  =100/1.41=70.9ml
 
Concentration (Molarity) = number of moles of solute/volume of the solution
   = (1.09/70.9)×100
  = 1.5M
 
 
Hope it helps.
Cheers!

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