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calculate the no. of moles in 34g of NH3

Mass ( m ) = 34g
Molar mass of NH3 (M) = 17g
no. Of moles (n) = m/M = 34/17 = 2 moles.

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molar mass of NH3 = 1*14+3*1
                                 = 14+3
                                =  17g
17g of NH3 =1 mole
1g of  NH3  = 1/17 mole
34g of NH3 = 1/17*34 mole
                   =  2 moles 

Therefore, no.of moles in 34g of NH3 = 2 moles
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