calculate the no of oxygen atoms present in 4.4 g of CO2

Molar mass CO2 = 44 g/mol
Therefore, number of moles in 4.4 g CO2 = 4.4/44 = 0.1 mol

Now,
1mol CO2 contains 6.022 x1023 molecules
0.1mol CO2 contains 6.022 x 1023 x 0.1 = 6.022 x 102222 molecules

Also,
1molecule of CO2 contains 2 atoms of oxygen
Therefore,

6.022 x1023 molecules of CO2 will contain 6.022 x 1022 x 2 = 1.204 x 1023 atoms of oxygen

  • 49

Molar mass CO2 = 44 g/mol
You have 4.4g , so you have 4.4/44 = 0.1 mol CO2
1mol CO2 has 6.022*10^23 molecules
0.1mol CO2 has (6.022*10^23)*0.1 = 6.022*10^22 molecules
1molecule of CO2 contains 2 atoms of O
Therefore, 6.022*10^22 molecules of CO2 will contain (6.022*10^22) *2 = 1.204*10^23 atoms O

  • 10

no of moles of co2= given mass/molecular mass

=4.4/44

= 0.1mole

1 mole of co2 contains 6.023 x 1023 oxygen atoms.

0.1 mole of co2 contains = 2 x 0.1 x 6.023 x 1023 oxygen atoms.

= 1.2 x 1023 oxygen atoms

  • 30
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