# Can any body solve this ? Please! answer fast.

If the cube is painted externally, taking the number of sections made as ‘n’,

Number of faces with no colour = $(n-2{)}^{3}$

Number of faces with 1 colour = $6\times (n-2{)}^{2}$

Number of faces with 2 colours = $12\times (n-2)$

Here, your n is 7. So number of 1 coloured faces will be $6\times (n-2{)}^{2}=6{\left(7-2\right)}^{2}=6\times {5}^{2}=6\times 25=150$** **

Regards

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