Can sm1 solve the 6th qstion?

Can sm1 solve the 6th qstion? construct APQR —AABC in which AB=6.2 crn, BC=5.4 cm and AC=4 cm. using factor — Q.2 Construct a AABC in which base BC=7 cm, altitude AD 5 cm and 3 cm. Construct another triangle whose sides are I — times the corresponding sides of AABC . Q.3. draw a circle of radius 6cm. From a point 10 cm away from its centre, construct the pair of tangents to the circle and measure their lengths. Q.4. Draw a pair of tangents to the circle of radius 5 cm which are inclined to each other at an angle of 600 Q.5. Draw two concentric circles of radii 3 cm and 5 cm . Taking a point on outer circle construct the pair of tangents to the other. Measure the length of a tangent and verify it by actual calculation. 9.6. Draw a parallelogram ABCD in which BC=5 cm, AB=3 cm and angle ABC=600, divide it into triangles BCD and ABD by the diagonal BD. Construct triangle BD'C' similar to triangle BDC with scale factor 4/3. XII AREAS RELATED TO CIRCLES (1 Mark) What is the perimeter of a semicircle with diameter 14 cm. 2. The radii of two circles are 5 cm & 12 cm. Find the radius of the circle whose area in the sum of areas d two circles.

Dear Student ,

To draw a parallelogram ABCD in which BC = 5 cm and AB = 3 cm and angle abc= 60 degree, follow the following steps:

(1) Draw a line segment AB = 3 cm
(2) At B, construct angle ABM = 60 degree.
(3) From BM, cut-off a line segment BC = 5 cm
(4) Now through the point A, draw AN||BC
(5) Through the point C, draw CD || BA, meeting AN at D.
Thus ABCD is the required parallelogram.
(6) Through diagonal BD, divide the parallelogram ABCD into two triangles BCD and ABD.
To construct the triangle BD'C' similar to triangle BDC with scale factor 4:3, we have

(1) Below BD make an acute angle DBX.
(2) Along BX, mark four points B₁_,B₂_, B₃_, and B₄ such that BB₁=B₁B₂=B₂B₃=B₃B₄
(3) Join B₃D
(4) From B₄ , draw B₄D' || B₃D meeting BD produced at D'
(5) From D', draw C'D' || CD meeting BD produced at C'.
Thus, BC'D' is the required triangle whose sides are 4/3 times the corresponding side of triangle BCD.

Regards

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