Can u make a quadratic equation for the following-

two years ago,jacob's age was 3 times the square of john's age. in 3 yrs time, john's age will be one fourth of jacob's age. find their present ages.

Dear user!

Let John's age before 2 years be x years old.

Then, Jacob's age before 2 years = 3x² years

So, present age of John = (x + 2) years

Present age of Jacob = (3x² + 2) years

After 3 years, John’s age = (x + 2 + 3) years = (x + 5) years

After 3 years, Jacob’s age = (3x² + 2 + 3) years = (3x² + 5) years

Cheers!