Can u solve any 5 problems

Dear Student,

4. we consider i₁ be the current flows through the first loop in clockwise direction and i₂ be the current flows through the second loop in anticlockwise direction in the circuit.
total current=i₁+i₂
$$\begin{gathered} for the first loop, \\ 10+1\times i_1+1\times \left(i_1+i_2\right)+1\times i_1=0 \\ 10+3i_1+i_2=0 \\ {i}_2=-10-3i_1............\left(1\right) \\ for the second loop, \\ 1\times i_2+1\times \left(i_1+i_2\right)+1i_2=0 \\ 3i_2+i_1=0 \\ 3\left(-10-3i_1\right)+i_1=0 \\ -9i_1+i_1=30 \\ {i}_1=-\frac{30}{8}=-3.75amp(negative sign for direction) \\ from \left(2\right), \\ {i}_2=-10-3\times \left(-3.75\right)=1.25amp \\ the current through ammeter=i_1+i_2=5amp \\ the pd for the first loop, \\ {V}_1=1\times 3.75+1\times 5+1\times 3.75=12.5V \\ the pd for the second loop, \\ {V}_2=1\times 1.25+1\times 5+1\times 1.25=7.5V \\ the pd across the voltmeter=V_1-V_2=5V \end{gathered}$$ Regards