can we prove this property of triangles on the same base and between same parrals are equal in area by 1/2 *base*height that the are between same base anb the height becomes the length between the parallels therefore if the base is 2 cm and the length between parallels is 5 cm then the area of 1st triangle will be 5cm 2
and the area of the 2nd triangle is also 5cm2.?plzzzzzzz help me fast i hav my exam next week only..........
Two triangles on the same base (or equal bases) and between the same parallel are equal in area
Suppose ABCD is a parallelogram whose one of the diagonal is AC. Let AN is perpendicular to DC.
The data provided by you is DC = 2 cm and AN = 5
area of ADC = ½ × 5 × 2 = 5 cm2
Therefore, the area of triangle ABC will also be equal to 5 cm2 .