Can you answer this question also ?
Q.22. In the given figure, a right LNM and a semicircle with MN as the diameter have been shown. What is the area of the given figure?

Dear student
By Pythagoras theorem in LMNLM2=LN2+MN2MN2=LM2-LN2MN=LM2-LN2MN=152-122MN=225-144MN=9cmSo, Area of triangle LMN=12×MN×LNArea of triangle LMN=12×9×12Area of triangle LMN=54cm2Radius of semicircle,r=MN2=92So, area of semicircle=πr22area of semicircle=12×227×92×92area of semicircle=178256area of semicircle=31.82cm2Area of given figure=Area of triangle LMN+area of semicircleArea of given figure=54+31.82Area of given figure=85.82cm2
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including the semi circle
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