Can you be please solve this question?????
Given that: ABCD is a parallelogram
To Prove : AP = CQ
Proof:
In Δ APB and Δ CQD
∠APB = ∠CQD [ EACH RIGHT ANGLE ]
AB = CD (opposite sides of parallelogram ABCD)
∠ABP = ∠CDQ (Alternate interior angles for AB||CD)
So, Δ APB is congruent to Δ CQD [ AAS ]
⇒ AP = CQ [CPCT]
