Can you please solve this problem for me. Please explain it clearly Share with your friends Share 1 Priyanka Sahu answered this Dear Student cos 50°2 sin 40° + 4cosec259° - tan231°3 tan245° - 23 tan 12° tan 78° sin 90°=cos90°-40°2 sin 40° + 4cosec259° - tan290°-59°3 tan245° - 23 tan90°-78° . tan 78° sin 90°=sin 40°2 sin 40° + 4cosec259° -cot259°3 tan245° - 23 cot 78° × tan 78° × sin 90°=12 + 4 × 13 ×12 - 23 × 1tan 78°× tan 78° × 1=12 + 43 - 23=3 + 8 - 46 = 76 Regards 1 View Full Answer
