Concentrated aqueous sulphuric acid is 98% h2so4 and has a density of 1.80 gm/L what is the molarity of solution?
Plz don't send any link as I have checked them all
Answrr of this ques. is 10M but I don't know the solution.
Plz help...........

Dear Student,

Please find below the solution to the asked query:

Given that conc.H₂SO₄ is present as 98% 
This means 98g of H₂SO₄ is present in 100g of solution.
Now, 
$$\begin{gathered} no.of moles =\frac{weight of H_{2}S{O}_4}{molar mass of H_{2}S{O}_4} \\ =\frac{98g}{98gmo{l}^{-1}} \\ = 1mol \end{gathered}$$

$$\begin{gathered} Density =\frac{mass of solution }{volume of solution } \\ volume of solution =\frac{100g}{1.8g/mL} \\ = 55.55mL \end{gathered}$$
$$\begin{gathered} Molarity =\frac{no.of moles of solute}{volume of solution in litres} \\ =\frac{1}{0.05555} \\ =18M \end{gathered}$$

[Please note that the unit of Density mentioned by you is wrong, it has to be 1.80g/mL]

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