Construct a ∆ABC, in whichBC= 4.7 cm, <B= 60 and AB + BC = 8.2 cm.

Follow the given steps to constant the ΔABC.

Step 1: Draw a line segment BC = 4.7 cm

Step 2: At B, draw an angle of 60°, say ∠XBC.

Step 3: Cut a line segment, BD = 8.2 cm (= AB + BC) on the ray BX.

Step 4: Join DC. Draw ∠DCY = ∠BDC. Let CY intersect BX in A.

Hence, ΔABC is the required triangle.