Construct a quadrilateral abcd in which ab=3.5cm bc=6.5cm angle a=60 degree angle c=120 degree and angle d=75 degree.
Write steps for construction also.
We know from angle sum property of quadrilateral ,
∠ A + ∠ B + ∠ C + ∠ D = 360° , So
60° +∠ B + 120° +75° = 360°
∠ B = 105°
We follow these steps to construct our quadrilateral ABCD from given information :
Step 1 : Draw line AB = 3.5 cm
Step 2 : With the help of protractor we form ∠ BAX = 60° and ∠ ABY = 105° .
Step 3 : We take radius of 6.5 cm and center " B " draw an arc that intersect our line BY at " C " .
Step 4 : Now with the help of protractor we form 120° angle at " C " and angle ray intersect line AX at " D " .
We get our required quadrilateral ABCD :
∠ A + ∠ B + ∠ C + ∠ D = 360° , So
60° +∠ B + 120° +75° = 360°
∠ B = 105°
We follow these steps to construct our quadrilateral ABCD from given information :
Step 1 : Draw line AB = 3.5 cm
Step 2 : With the help of protractor we form ∠ BAX = 60° and ∠ ABY = 105° .
Step 3 : We take radius of 6.5 cm and center " B " draw an arc that intersect our line BY at " C " .
Step 4 : Now with the help of protractor we form 120° angle at " C " and angle ray intersect line AX at " D " .
We get our required quadrilateral ABCD :