construct a triangle ABC in which B=60 C=45 and AB+BC +CA=8.5cm  plzz   dont send links  solve it plzz tommorow is my exam

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$$\begin{gathered} \mathrm{Step} 1: \mathrm{Draw} \mathrm{a} \mathrm{line} \mathrm{segment} \mathrm{PQ} \left(= \mathrm{AB} + \mathrm{BC} + \mathrm{CA}\right) = 8.5 \mathrm{cm}. \\ \mathrm{Step} 2: \mathrm{Draw} \mathrm{an} \mathrm{angle} \mathrm{of} 60° \mathrm{at} \mathrm{P} \mathrm{and} \mathrm{an} \mathrm{angle} \mathrm{of} 45° \mathrm{at} \mathrm{Q}. \\ \mathrm{Step} 3: \mathrm{Bisect} \angle \mathrm{P} \mathrm{and} \angle \mathrm{Q}. \mathrm{Let} \mathrm{the} \mathrm{bisectors} \mathrm{of} \angle \mathrm{P} \mathrm{and} \angle \mathrm{Q} \mathrm{intersect} \mathrm{in} \mathrm{A}. \\ \mathrm{Step} 4: \mathrm{Draw} \mathrm{perpendicular} \mathrm{bisector} \mathrm{DE} \mathrm{of} \mathrm{AP} \mathrm{which} \mathrm{intersect} \mathrm{PQ} \mathrm{in} \mathrm{B} \mathrm{and} \mathrm{FG} \mathrm{of} \mathrm{AQ} \mathrm{which} \mathrm{intersect} \mathrm{PQ} \mathrm{in} \mathrm{C}. \\ \mathrm{Step} 5: \mathrm{Join} \mathrm{AB} \mathrm{and} \mathrm{AC}. \\ \therefore \mathrm{\Delta ABC} \mathrm{is} \mathrm{the} \mathrm{required} \mathrm{triangle}. \end{gathered}$$


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