Construct a triangle ∆ABC in which BC= 6cm angle A =100° angle B =60°

Dear Student

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  • 1
  1. draw BC= 8cm with a scale.
  2. at B, draw a 60o angle.
  3. (according to angle sum property, sum of all angles = 180)
  4. angle C = 20 o. [180o - (100o + 60o)
  5. draw angle C = 20o.
  6. extend angle A and B to intersect.
  7. name this intersection as A
  8. measure A= 20o
hope this helps ;)
 
  • 1
sorry, mistake : BC = 6cm
 
  • 0
draw anything of anything
  • -1
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