construct a triangle ABC in which BC=6cm, CA=5cm and AB=4cm. Construct triangle similar to it such that each side of similar triamgleis 5/3 times corresponding sides of triangle ABC. write steps

Step1=Draw the 4cm line AB and set the 5cm length in compass and draw the arc from point A then set 6cm lenght in compass and draw the arc which cuts the 5cm arcStep2=Name the cut point of arcs that is C and join to the A and B point.Step3=Now draw the any acute angle with the line at point A and cut it into 5 any equal parts .Step4=The 3rd cut in the line join it to the point B .Step5=Now draw the parllel line from 5th cut to the line joining to the 3rd cut and point B.Step6=Now increse the line AB which cuts the parllel line at the point B'.Step7=Now draw the parllel line of BC from to B' and increse the AC line which cuts the parllel line of BC at the pont C'Now we have the requaired triangle.

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  1. draw a line segment AB=4cm
  2. take compass measure 5cm , keeping the tip on A draw an arc
  3. then take 6cm on compass, keeping the tip on B draw an arc
  4. mark the point at where the two lines intersect as C
  5. then draw AX
  6. ​divide AX into 5 parts
  7. join BX​3
  8. draw a line parallel to BX​3 BX5
  9. then draw another line parallel
  10. u will get the desired triangle
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