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construct a triangle in which base is of length 6.2 cm , base angle is 105* and sum of other 2 sides of a triangle is 10.1 cm ??     

Dear Student ,
 
Please find below the solution to the asked query :

Steps of construction:1 Draw a line segment AB=6.2 cm2 At A , Construct an angle YAB=105°.3 Taking A as centre , draw an arc of length 10.1 cm , which intersects AY at D.4 Join DB.5 Now , draw the perpendicular bisector of DB , which intersects AD at C.6 Join AC.Thus △ABC is the required triangle.

 
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PLZ FRIENDS & EXPERTS ANS MY QUSTION FAST ??
 
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sorry its not possible to explain u this thing here.
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The qn is from construction chapter.

STEPS OF CONSTRUCTION : ( for the given qn )
  • We can consider the triangle as A,B and C.
  • Now draw a ray BX.
  • From BX cut off BC = 6.2cm.
  • At B, construct angleCBY = 105*
  • From BY, cut off BD = 10.1 cm ( since sum of 2 sides (i.e) AB+BC=10.1 cm)
  • Join D and C.
  • Bisect DC such that the bisector of DC meets BD at A.
  • Join AC.
  • Thus , triangleABC is the required triangle.
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