construct an equilateral triangle of 5.2cm each.now construct angle bisectors of any two angle. their intersecting point lies where? Share with your friends Share 0 Rupak Bhattacharya answered this STEPS :1. Draw a line segment BC = 5.2 cm2. With B as centre draw an arc of radius 5.2 cm3. With C as centre draw an arc of radius 5.2 cm that intersects previous arc at A.4. ABC is the required triangle.5. With B as centre, draw an arc that cut AB at L and BC at M.6. Taking L amd M as centre, draw arcs that intersect at N.7. With C as centre, draw an arc that cut AC at P and BC at Q.8. Taking P and Q as centre, draw arcs that intersect at R.9. Join BN and CR, produce them that intersect at O.10. With O as centre draw a circle that touches the sides of ∆ABC.Hence, the bisectors of angles of equilateral ∆ intersects at the centre of incircle. 1 View Full Answer Nancy Bansal answered this in the cicumcentre of the triangle I hope so......... 0