construct triangle ABC in which perimeter is 15 cm and base angle B =60 and angle C=75.
Steps of construction:
1.Draw a line segment PQ = 15cm .( AB + BC + CA ).
2 .At P construct an angle of 60° , at Q an angle of 45° .
3. Bisect these angles. Let the bisectors of these angles intersect at a point A.
4. Draw perpendicular bisectors DE of AP to intersect PQ at B and FG of AQ to
intersect PQ at C.
5. Join AB and AC
6 Thus ABC is the required triangle.
1.Draw a line segment PQ = 15cm .( AB + BC + CA ).
2 .At P construct an angle of 60° , at Q an angle of 45° .
3. Bisect these angles. Let the bisectors of these angles intersect at a point A.
4. Draw perpendicular bisectors DE of AP to intersect PQ at B and FG of AQ to
intersect PQ at C.
5. Join AB and AC
6 Thus ABC is the required triangle.