Cos6A-cos4A/sin6A+sin4A=tanA This question has not been answered yet! Don't worry! You can check out similar questions with solutions below ... sin3A sin6A + sin4A sin13A/ SinA cos2A + sin3A cos6A + sin4A ... sin6A+cos6A+sin4A + cos4A 2(sin6A - cos6A) - 3(sin4A + cos4A) + 4 Prove that : 3 ( sin4A + cos4A ) - 2 (sin6A + cos6A ) = 1 2(sin6A + cos6A) -3(sin4A + cos4A) + 1 = 0
