# Dear Experts,How F=qE?

From Coulomb's law, the force on charge q due to a charge Q is given by:

$\overrightarrow{F}=\frac{1}{4\pi {\epsilon}_{o}}\frac{qQ}{{r}^{2}}\hat{r},wherer=dis\mathrm{tan}cebetweenthechargesqandQ.$

The electric field due to charge Q is given as:

$\overrightarrow{E}=\frac{1}{4\pi {\epsilon}_{o}}\frac{Q}{{r}^{2}}\hat{r}$

So, comparing both equations we can write:

$\overrightarrow{F}=q\overrightarrow{E}$

It is the force on the charge q due to the field generated by Q.

Regards

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