Derivative of root cosec x Share with your friends Share 2 Manbar Singh answered this Let y = cosec x⇒y = cosec x1/2⇒log y = log cosec x1/2⇒log y = 12 log cosec xdifferentiating both sides with respect to x, we get1ydydx = 12×1cosec x × - cot x . cosec x⇒1ydydx = -cot x2⇒dydx = -y×cot x2⇒dydx = -12cosec x . cot x 0 View Full Answer