describe the following in roster form a={x: x is a positive factor of (2^n-1)(2?-1) where 2^n-1 is prime}


Dear Student,
If your query is a={x:x is a positive factor of (2^(n-1))(2^n-1), where 2^(n-1) is prime}, then here is the solution;

2n- 1(2n - 1) = 21(2n - 1)

= 2(22 - 1) [ because 2n - 1 = 21 so n- 1 = 1 and therefore n = 2]

= 2(4 - 1) = 2 x 3 = 6

therefore , a = {1,2,3,6} [because 1,2,3 and 6 are factors of 6}

Regards.

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