Determine the antiderivative F of “f” , which is defined by f (x) = 4x3 – 6, where F (0) = 3

Dear student,

Given function: f (x) = 4x3 – 6

Now, integrate the function:

∫4x3 – 6 = 4(x4/4)-6x + C

∫4x3 – 6 = x4 – 6x + C

Thus, the antiderivative of the function, F is x4 – 6x + C, where C is a constant

Also, given that, F(0) = 3,

Now, substitute x = 0 in the obtained antiderivative function, we get:

(0)4 – 6(0) + C = 3

Therefore, C = 3.

Now, substitute C = 3 in antiderivative function

Hence, the required antiderivative function is x4 – 6x + 3
Regards

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X^4 -3X^2 +3 IS ANSWER
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