Determine the antiderivative F of “f” , which is defined by f (x) = 4x3 – 6, where F (0) = 3
Dear student,
Given function: f (x) = 4x3 – 6
Now, integrate the function:
∫4x3 – 6 = 4(x4/4)-6x + C
∫4x3 – 6 = x4 – 6x + C
Thus, the antiderivative of the function, F is x4 – 6x + C, where C is a constant
Also, given that, F(0) = 3,
Now, substitute x = 0 in the obtained antiderivative function, we get:
(0)4 – 6(0) + C = 3
Therefore, C = 3.
Now, substitute C = 3 in antiderivative function
Hence, the required antiderivative function is x4 – 6x + 3
Regards