diagonals of a quadrilateral abcd bisect each other , if angle A=35,then angle B is

As we know that if the diagonals of a quadrilateral bisect each other then the quadrilateral is a parallelogram.
Hence  ABCD is a parallelogram
$$\begin{gathered} Now \angle DAB and \angle ABC are \mathrm{co}nsecutive interior angles as AD\parallel BC and AB is a transversal \\ and we know that sum of consecutive interior angles is 180° \\ \therefore \angle DAB+\angle ABC=180° \\ \Rightarrow \angle ABC = 180°-\angle DAB =180°-35°=145° \end{gathered}$$